If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(F)=2F^2-12F-23
We move all terms to the left:
(F)-(2F^2-12F-23)=0
We get rid of parentheses
-2F^2+F+12F+23=0
We add all the numbers together, and all the variables
-2F^2+13F+23=0
a = -2; b = 13; c = +23;
Δ = b2-4ac
Δ = 132-4·(-2)·23
Δ = 353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{353}}{2*-2}=\frac{-13-\sqrt{353}}{-4} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{353}}{2*-2}=\frac{-13+\sqrt{353}}{-4} $
| (3x+4)=(5x-60) | | –2t=62 | | 1.5x+1Y=4.46 | | -3w=93 | | 2x-30=460 | | 6x16=15x+15 | | 3x(x+24)=90 | | 9n-3=1 | | H=8g+2 | | 21d-18=6(3+4d)-3d | | -5w-11=21 | | 20+7x=-8 | | 8-(c-4)=12-c | | 3(b-12)+b=1/2(12-8b) | | -3x²+9=30 | | -3{x^2}+9=30 | | -37=8r-3 | | a+6=-a+12 | | 6+2|2x-3|=28 | | (4+4x)=36 | | Z2=-3-2i×-3-2i | | x=13,x=−5 | | x+88+10x-51=360 | | x−4=6x+26A | | 7x+2-3x+5=47 | | 12+3=8x-7 | | 7k-16=3k+72 | | (5x-5)=(3x+25) | | 250+16=210+18x | | 20/q+1=q+2 | | 2x+28=58 | | 76*2a=(8a-6)(a+5) |